Thực hiện chuỗi biến hóa sau: CH3COONa➝CH4➝C2H2➝C4H4➝C4H10➝C2H4➝C2H5OH➝C2H4➝PE giải dùm mình cần gấp tối nay luc 8h15 giúp dùm mình đang gấp

Đáp án:

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Giải thích các bước giải:

`-` `CH_3COONa+NaOH` $\xrightarrow[xt]{t^o}$ `CH_4+Na_2CO_3`

`-` `2CH_4` $\xrightarrow[làm lạnh nhanh]{1500^{o}C}$ `C_2H_2+3H_2`

`-` `2C_2H_2→C_4H_4`

`-` `C_4H_4+3H_2` $\xrightarrow[Ni]{t^o}$ `C_4H_10`

`-` `C_4H_10` $\xrightarrow[xt]{t^o, p}$ `C_2H_4+C_2H_6`

`-` `C_2H_4+H_2O` $\xrightarrow[H_2SO_4]{t^o}$ `C_2H_5OH`

`-` `C_2H_5OH` $\xrightarrow[H_2SO_4]{170^{o}C}$ `C_2H_4+H_2O`

`-` `nC_2H_4` $\xrightarrow[xt]{t^o, p}$ $(\kern-6pt- CH_2-CH_2 -\kern-6pt)_n$

Bạn tham khảo!

Đáp án+Giải thích các bước giải:

$\bullet$ Đề)

$CH_3COONa$ $\xrightarrow{1}$ $CH_4$ $\xrightarrow{2}$ $C_2H_2$ $\xrightarrow{3}$ $C_4H_4$ $\xrightarrow{4}$ $C_4H_{10}$ $\xrightarrow{5}$ $C_2H_4$ $\xrightarrow{6}$ $C_2H_5OH$ $\xrightarrow{7}$ $C_2H_4$ $\xrightarrow{8}$ PE

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$\bullet$ Bài làm)

1) $CH_3COONa+NaOH$ $\xrightarrow[CaO]{t^o}$ $Na_2CO_3+CH_4$

2) $2CH_4$ $\xrightarrow[\text{làm lạnh nhanh}]{1500^{0}}$ $C_2H_2+3H_2$

3) $2C_2H_2$ $\xrightarrow{CuCl_2/NH_4Cl}$ $C_4H_4$

4) $C_4H_4+2H_2$ $\xrightarrow[Ni]{t^o}$ $C_4H_{10}$

5) $C_4H_{10}$ $\xrightarrow{\text{crackinh}}$ $C_2H_6+C_2H_4$

6) $C_2H_4+H_2O$ $\xrightarrow[Axit]{H_2O}$ $C_2H_5OH$

7) $C_2H_5OH$ $\xrightarrow[H_2SO_4]{>170^{0}}$ $C_2H_4+H_2O$

8) $nCH_2=CH_2$ $\xrightarrow[xt]{t^{0}, p}$ $(\kern-6pt- CH_2-CH_2 -\kern-6pt)_n$