Rút gọn: $4.\sqrt[4]{\frac{a^{4}.b^{2}.(a + c )}{8.( a + c ).b^{2}} }$ chi tiết
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4$\sqrt[4]{\frac{a^{4}.b^{2}.(a+c)}{8(a+c).b^{2}}}$ =4.$\sqrt[4]{\frac{a^{4}}{8}}$ =$\sqrt[4]{\frac{256.a^{4}}{8}}$ =$\sqrt[4]{32.a^{4}}$ =a$\sqrt[4]{32}$
4$\sqrt[4]{\frac{a^{4}.b^{2}.(a+c)}{8(a+c).b^{2}}}$ =4.$\sqrt[4]{\frac{a^{4}}{8}}$ =$\sqrt[4]{\frac{256.a^{4}}{8}}$ =$\sqrt[4]{32.a^{4}}$ =a$\sqrt[4]{32}$
