Một hộp chứa 9 thể đánh số từ 1 đến 9. Chọn ngẫu nhiên hai thẻ. Tính xác suất để tổng hai số trên hai thẻ đó bằng 7.

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Đáp án: $P(A)=\dfrac{1}{12}$

 

Giải thích các bước giải:

   Số phần tử của không gian mẫu là:

→ $n(\Omega)=C^2_9=36$

  Gọi $A$ là biến cố ''Tổng hai số trên 2 thẻ đó bằng 7''

 $A=\{(1;6),(2;5),(3;4)\}$

→ $n(A)=3$

⇒ $P(A)=\dfrac{3}{36}=\dfrac{1}{12}$

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