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Đáp án:
$\lim \:\left(2n+1\right)^2\left(\dfrac{3}{n^2}+2-\dfrac{1}{n^2}+3n-1\right)$ $=+\infty \:\:$
Giải thích các bước giải:
$\lim \:\left(2n+1\right)^2\left(\dfrac{3}{n^2}+2-\dfrac{1}{n^2}+3n-1\right)$
$=\lim \:\left(2n+1\right)^2\:.\:\:\lim \:\dfrac{3}{n^2}+2-\dfrac{1}{n^2}+3n-1$
$=\infty \:.\:\infty \:\:$
$=+\infty \:\:$