1 câu trả lời
2sin(450+3x)+1=0⇔sin(450+3x)=−12⇔[450+3x=−300+k3600450+3x=1800+300+k3600⇔[3x=−750+k36003x=1650+k3600⇔[x=−250+k1200x=550+k1200(k∈Z)
2sin(450+3x)+1=0⇔sin(450+3x)=−12⇔[450+3x=−300+k3600450+3x=1800+300+k3600⇔[3x=−750+k36003x=1650+k3600⇔[x=−250+k1200x=550+k1200(k∈Z)