2 câu trả lời
$2 \sin x+\sqrt{3}=0$
$\Leftrightarrow \sin x=-\frac{\sqrt{3}}{2}$
$\Leftrightarrow\left[\begin{array}{l}x=-\frac{\pi}{3}+k 2 \pi \\ x=\frac{4 \pi}{3}+k 2 \pi\end{array}\right.$
𝐆𝐢𝐚̉𝐢 𝐭𝐡𝐢́𝐜𝐡 + đ𝐚́𝐩 𝐚́𝐧
𝟐 𝐬𝐢𝐧 𝐱 + √𝟑 = 𝟎
⇒ 𝐬𝐢𝐧 𝐱 = - √³_
₂
⌈𝐱 = - π͟ + 𝐤𝟐π
⇒ | 𝟑
⌊ 𝐱 = 𝟒͟ ͟π͟ + 𝐤𝟐π
𝟑
𝐂𝐡𝐮́𝐜 𝐦𝐮̛̀𝐧𝐠 𝐧𝐚̆𝐦 𝐦𝐨̛́𝐢 𝐯𝐯
# 𝐇𝐨𝐢𝐝𝐚𝐩𝟐𝟒𝟕 𝐤𝐢𝐞𝐮𝐚𝐧𝐡𝟔𝟒
