2 câu trả lời
(1)Cu(OH)2⟶CuO+H2O
(2) CuO + H2SO4 → CuSO4 + H2O
(3)BaCl2+CuSO4→CuCl2+BaSO4
(4)2NaOH+CuCl2→Cu(OH)2+2NaCl
-$Cu(OH)_2$$\xrightarrow[a]{t^o}$CuO+$H_2O$
-CuO+$H_2$$SO_4$→$CuSO_4$+$H_2O$
-$CuSO_4$+$BaCl_2$→$CuCl_2$+$BaSO_4$
-$CuCl_2$+2NaOH→$Cu(OH)_2$+2NaCl