Cu(OH)2-->CuO-->CuSO4-->CuCl2-->Cu(OH)2

2 câu trả lời

(1)Cu(OH)2⟶CuO+H2O

(2)  CuO + H2SO4 → CuSO4 + H2O

(3)BaCl2+CuSO4CuCl2+BaSO4

(4)2NaOH+CuCl2Cu(OH)2+2NaCl

-$Cu(OH)_2$$\xrightarrow[a]{t^o}$CuO+$H_2O$

-CuO+$H_2$$SO_4$→$CuSO_4$+$H_2O$

-$CuSO_4$+$BaCl_2$→$CuCl_2$+$BaSO_4$

-$CuCl_2$+2NaOH→$Cu(OH)_2$+2NaCl

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