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3:(x−12)=(x−12):27⇒3x−12=x−1227⇒(x−12)2=3.27⇒(x−12)2=81=92=(−9)2⇒[x−12=9x−12=−9⇒[x=9+12x=−9+12⇒[x=192x=−172
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3:(x−12)=(x−12):27⇒3x−12=x−1227⇒(x−12)2=3.27⇒(x−12)2=81=92=(−9)2⇒[x−12=9x−12=−9⇒[x=9+12x=−9+12⇒[x=192x=−172