(2,5-3x):5/3=(8/5+2x):(-8/17).Tìm x

\(\begin{array}{l} \left( {2,5 - 3x} \right):\frac{5}{3} = \left( {\frac{8}{5} + 2x} \right):\left( {\frac{{ - 8}}{{17}}} \right)\\ \Rightarrow \left( {\frac{5}{2} - 3x} \right).\frac{3}{5} = \left( {\frac{8}{5} + 2x} \right).\left( {\frac{{17}}{{ - 8}}} \right)\\ \Rightarrow \left( {\frac{5}{2} - 3x} \right).\frac{3}{5} = \left( {\frac{8}{5} + 2x} \right).\frac{{ - 17}}{8}\\ \Rightarrow \frac{3}{2} - \frac{9}{5}x = \frac{{ - 17}}{5} + \frac{{ - 17}}{4}x\\ \Rightarrow - \frac{9}{5}x - \frac{{ - 17}}{4}x = \frac{{ - 17}}{5} - \frac{3}{2}\\ \Rightarrow \frac{{ - 9}}{5}x + \frac{{17}}{4}x = \frac{{ - 34}}{{10}} - \frac{{15}}{{10}}\\ \Rightarrow \left( {\frac{{ - 9}}{5} + \frac{{17}}{4}} \right)x = \frac{{ - 49}}{{10}}\\ \Rightarrow \frac{{49}}{{20}}x = \frac{{ - 49}}{{10}}\\ \Rightarrow x = \frac{{ - 49}}{{10}}:\frac{{49}}{{20}} = - 2 \end{array}\)