Cho 21,2 gam Na2Co3 tác dụng vừa đủ với dung dịch HCl 2M tính thể tích dung dịch HCL tham gia phản ứng

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Đáp án:

 

Giải thích các bước giải:

PTHH: `Na_2 CO_3 + 2HCl -> 2NaCl + CO_2↑ + H_2 O`

`nNa_2 CO_3 = (21,2)/(106) = 0,2 (mol)`

Theo PT: `nHCl = nNa_2 CO_3 . 2 = 0,2 . 2 = 0,4 (mol)`

`-> V_{ddHCl} = n/(CM) = (0,4)/2 = 0,2 (l) = 200 (ml)`

 

n Na2CO3 = 21,2 : 106 = 0,2 mol Phương trình phản ứng: Na2CO3 + 2HCl → 2NaCl + H2O + CO2 n HCl = 0,2. 2 :1 = 0,4 mol V H2SO4 = 0,4 : 2= 0,2 l
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