c) 3− {24:[26−(18:9+12)]} CÂU 2: Tìm x, biết: a) (x−35):5=10 b) 3(x+1)+12=62 Help

`c)`

`3 - {24 : [ 26 - (18 : 9 + 12) ] } `

` = 3 - {24 : [ 26 - (2 + 12) ] }`

` = 3 - [ 24 : (26 - 14) ] `

` = 3 - (24 : 12)`

` = 3 - 2`

` = 1`

Câu `2`

`a)`

`(x-35) : 5 = 10`

`=> x-35=10.5`

`=>x-35=50`

`=>x=50+35`

`=>x=85`

Vậy `x=85`

`b)`

`3 (x+1) + 12 = 62`

`=> 3 (x+1) = 62 - 12`

`=> 3 (x+1) = 50`

`=> x+1 = 50 : 3`

`=>x+1=50/3`

`=>x=50/3-1`

`=>x=47/3`

Vậy `x=47/3`

`c)`

`3 - { 24 : [ 26 - ( 18 : 9 + 12 ) ] }`

`= 3 - { 24 : [ 26 - ( 2 + 12 ) ] }`

`= 3 - { 24 : [ 26 - 14 ] }`

`= 3 - { 24 : 12 }`

`= 3 - 2`

`= 1`

$\text{ Câu 2 : }$

`a)`

`( x - 35 ) : 5 = 10`

`=> x - 35 = 10. 5`

`=> x - 35 = 50`

`=> x = 50 + 35`

`=> x = 85`

$Vậy$ `x = 85`

`b)`

`3( x + 1 ) + 12 = 62`

`=> 3( x + 1 ) = 62 - 12`

`=> 3( x + 1 ) = 50`

`=> x + 1 = 50 : 3`

`=> x + 1 = 50/3`

`=> x = 50/3 - 1`

`=> x = 47/3`

$Vậy$ `x = 47/3`