2 Div 3 + 2 Mod 3 + 3 Div 2 - 3 Mod 2

2 câu trả lời

2 Div 3 + 2 Mod 3 + 3 Div 2 - 3 Mod 2

= 0 + 2 + 1 - 1

= 2

Code:

uses crt;
begin
    clrscr;
    write(2 Div 3 + 2 Mod 3 + 3 Div 2 - 3 Mod 2);
// readln;
end.

`2` Div `3 + 2` Mod `3 + 3` Div `2 - 3` Mod `2`
`= 0 + 2 + 1 - 1`

`=2+1-1`

`=3-1`
`= 2`

Code: