2 câu trả lời
2 Div 3 + 2 Mod 3 + 3 Div 2 - 3 Mod 2
= 0 + 2 + 1 - 1
= 2
Code:
uses crt;
begin
clrscr;
write(2 Div 3 + 2 Mod 3 + 3 Div 2 - 3 Mod 2);
// readln;
end.
`2` Div `3 + 2` Mod `3 + 3` Div `2 - 3` Mod `2`
`= 0 + 2 + 1 - 1`
`=2+1-1`
`=3-1`
`= 2`
Code: